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what is the ratio of de-Broglie wavelength of electron in the second and third Bohr orbits in the hydrogen atoms?A. `2//3`B. `3//2`C. `4//3`D. `3//4` |
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Answer» Correct Answer - A `(2pir_2) = 2lambda_2` (2pir_3) = 3lambda_3` `:. (lambda_2)/(lambda_3) = (3r_2)/(2r_3)` Now, `r prop n^2` `:. (r^2)/(r^3) = ((2)/(3))^2` Substituting in Eq. (i), we get `lambda_2)/(lambda_3) = (2)/(3)` |
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