1.

what is the ratio of de-Broglie wavelength of electron in the second and third Bohr orbits in the hydrogen atoms?A. `2//3`B. `3//2`C. `4//3`D. `3//4`

Answer» Correct Answer - A
`(2pir_2) = 2lambda_2`
(2pir_3) = 3lambda_3`
`:. (lambda_2)/(lambda_3) = (3r_2)/(2r_3)`
Now, `r prop n^2`
`:. (r^2)/(r^3) = ((2)/(3))^2`
Substituting in Eq. (i), we get
`lambda_2)/(lambda_3) = (2)/(3)`


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