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What is the relation between the entry and exit entropy of an actual supersonic diffuser?(a) s1 = s2(b) s1 > s2(c) s1 < s2(d) s1 s2 = 1The question was asked in exam.Asked question is from Compressible Flow through Diffusers topic in portion Compressible Flow through Nozzles, Diffusers and Wind Tunnels of Aerodynamics

Answer»

Correct option is (c) s1 < s2

To elaborate: When the flow INTERACTS with the oblique shock waves inside the supersonic diffuser, the flow diffuses to a slower velocity. This results in a normal shock wave at the end of the diffuser. Thus the EXIT ENTROPY is HIGHER than the entropy at the inlet section.



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