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What is the sum of first n terms of the AP, a, 3a, 5a,…………. |
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Answer» AP is a, 3a, 5a,….. Here, a = a, d = 2a Sum = Sn = n/2 [2a + (n-1)d] = n/2[2a + 2an – 2a] = an2 |
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