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What is the temperature required in presence of molybdenum and iron for nitrogen to combine with hydrogen?(a) 123 Kelvin(b) 273 Kelvin(c) 673 Kelvin(d) 473 KelvinI had been asked this question in exam.Question is from Properties of Dihydrogen topic in division Hydrogen of Chemistry – Class 11

Answer»

Right answer is (C) 673 Kelvin

The explanation: At 673 Kelvin and 200 atmospheric pressure, one mole of nitrogen combines with three moles of hydrogen in presence of iron and molybdenum in ORDER to form 2 moles of ammonia and the ENTHALPY CHANGE is 92.6 KJ per Mol, the enthalpy here change is negative.



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