InterviewSolution
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InterviewSolution
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What is the tension in a rod of length length L and mass M at a distance y from`F_(1)` when the rod is acted on by two unequal force `F_(1)` and `F_(2) ( lt F_(1))` as shown in. |
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Answer» As is clear from (APC) 3 Net force on the rod ` f = F_(1) - F_(2) ` Acceleration of rod ` a = (f)/(M) = ((F_(1) - F_(2)))/(M) , along F_(1) ` Mass of part AB of the rod ` = ((M)/(L))y ` If T is tension in the rod at B then equation of motion of portion AB of the rod ` F_(1) - T = ma = ((m)/(L) y) ((F_(1) - F_(2))/(M)) ` ` = (F_(1) - F_(2)) (y)/(L)` `T = F_(1) (1- (y)/(L)) + F_(2) ((y)/(L))` ` T = F_(1) (1 - (y)/(L))+ F_(2) (y/(L)) ` This is the desired result |
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