1.

What is the value of (2sec 45o + tan 30o)?1). (2√6 + 1)/√32). √33). (2√2 + 3)/√64). (9 + 2√3)/9

Answer»

Since, we know that SEC 45 = √2 and tan 30 = 1/√3, PUT this in the REQUIRED equation

⇒ 2 sec 45o + tan 30o = 2 × √2 + 1/√3 = (2√6 + 1)/√3

∴ The VALUE of 2 sec 45o + tan 30o is (2√6 + 1)/√3



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