1.

What is the value of sec (90 – θ)°. sin θ sec 45°?(a) 1 (b) \(\frac{\sqrt3}{2}\) (c) √2 (d) √3

Answer»

(c) √2

sec (90 – θ)° sin θ sec 45° 

= cosec θ sin θ. (√2) = \(\frac1{sin\,\theta}\) . sin θ = √2 = √2.



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