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What is the value of tan (–1575°)?(a) 1 (b) \(\frac12\) (c) 0 (d) –1 |
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Answer» (a) 1 tan (– 1575°) = – tan (1575°) (∵ tan (–θ) = – tanθ) = – tan (4 × 360° + 135°) = – tan (135°) (∵ tan (n.360° + θ) = tan θ) = – tan (90° + 45°) (∵ tan (90° + θ) = – cot θ) = – (– cot 45°) = cot 45° = 1. |
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