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What is the velocity of maximum specific air range of the engine when the maximum air speed is 400m/s and the exponential value is 0.2?(a) 300.84(b) 380.43(c) 440.76(d) 494.37I had been asked this question in quiz.This intriguing question comes from Cruising Performance topic in division Cruising Performance of Aircraft Performance

Answer»

Correct choice is (d) 494.37

To explain I would say: The answer is 494.37.

Given n=0.2, VMD=400m/s. From the FORMULA \(\big[\frac{3-n}{1+n}\big]^{\frac{1}{4}}\)Vmd. On SUBSTITUTING the values we GET \([\frac{3-0.2}{1+0.2}]^{\frac{1}{4}}\)*400=494.37.



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