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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm

Answer» Actual needed value `= l(b + 20)`
`= lb + 20l`
`lb = csa + 20l`
`b = ( pi r l + 20l)/l`
`= (22/7 xx 6 xx 10 + 20 xx 3)/3 `
`= (1320 + 420)/21 = 83m`
`b = 83 m - 0.143m`
`= 82.857m`
now for the cone, `3l = pi xx 6 xx sqrt(8^2 + 6^2)`
`l = 22/7 xx 2 xx 10= 62m + 6/7 m`
`L= l+ 20cm`
`= 62m + (6/7 xx100cm)= `
`~~ 63m `
answer


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