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What number should be subtracted from \((\frac{3}{4}-\frac{2}{3})\) to get \(\frac{-1}{6}\) ? |
Answer» Let us consider a number as x to be subtracted from (3/4 – 2/3) to get -1/6 \((\frac{3}{4}-\frac{2}3)-x=\frac{-1}6\\x=\frac{3}{4}-\frac{2}{3}+\frac{1}{6}\\x=\frac{(3\times3-2\times4)}{12}+\frac{1}{6}\\=\frac{(9-8)}{12}+\frac{1}{6}\\=\frac{(1\times1+1\times2)}{12}\\=\frac{3}{12}\\=\frac{1}{4}\) \(\therefore\) the required number is \(\frac{1}{4}\) |
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