What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat

1.	What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine?
Answer» Efficiency of heat engine `(eta) = (T_(2)-T_(1))/(T_(2))` or `eta = 1 -(T_(1))/(T_(2)) = 10%` Therefore, `(T_(1))/(T_(2)) = 1- 0.1` `(T_(1))/(T_(2)) xx 100 = (1-0.1) xx 100 = 90` or `T_(1) = 90% of T_(2)`

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What percentage `T_(1)` is of `T_(2)` for a `10%` efficiency of a heat engine?

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