1.

What was the day of the week on 16th April, 2000 ?

Answer»

16th April, 2000 = (1999 years + Period from 1st Jan., 2000 to 16th A) 

Counting of odd days: 

1600 years have 0 odd day. 300 years have 1 odd day. 

99 years = (24 leap years + 75 ordinary years) 

= [(24 x 2) + (75 x 1)] odd days = 123 odd days 

= (17 weeks + 4 days) = 4 odd days. 

Jan. Feb. March April 

31 + 29 + 31 + 16 = 107 days = (15 weeks + 2 days) = 2 odd, 

Total number of odd days = (0 + 1 + 4 + 2) odd days = 7 odd days = 0 odd day. Hence, the required day was 'Sunday'.



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