1.

What was the day of the week on 16th August, 1947? 

Answer»

15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th 

Counting of odd days: 

1600 years have 0 odd day. 300 years have 1 odd day. 

47 years = (11 leap years + 36 ordinary years) 

= [(11 x 2) + (36 x 1») odd days = 58 odd days = 2 odd days. 

Jan. Feb. March April May June July Aug. 

31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 

= 227 days = (32 weeks + 3 days) = 3, 

Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days. 

Hence, the required day was 'Saturday'. 



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