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What was the day of the week on 16th August, 1947? |
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Answer» 15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th Counting of odd days: 1600 years have 0 odd day. 300 years have 1 odd day. 47 years = (11 leap years + 36 ordinary years) = [(11 x 2) + (36 x 1») odd days = 58 odd days = 2 odd days. Jan. Feb. March April May June July Aug. 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227 days = (32 weeks + 3 days) = 3, Total number of odd days = (0 + 1 + 2 + 3) odd days = 6 odd days. Hence, the required day was 'Saturday'. |
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