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What will be the approximate change in the surface area of a cube of side xm caused by increasing the side by 2%.(a) 0.24x(b) 2.4x^2(c) 0.4x^2(d) 0.24x^2I got this question in a national level competition.I'm obligated to ask this question of Derivatives Application topic in division Application of Derivatives of Mathematics – Class 12

Answer»

The correct OPTION is (d) 0.24x^2

Easy EXPLANATION: Let the edge of the CUBE be x. Given that dx or Δx is equal to 0.02x(2%).

The surface area of the cube is A=6x^2

Differentiating w.r.t x, we GET

\(\frac{dA}{dx}\)=12x

dA=(\(\frac{dA}{dx}\))Δx=12x(0.02x)=0.24x^2

Hence, the approximate change in volume is 0.24x^2.



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