1.

What will be the efficiency of Carnot engine if its source is at 500 K and sink at 300 K?

Answer»

Efficiency, η = (T- T1)/T2
T2 = 500 K (temperature of the source)
T1 = 300 K (temperature of the sink)
Therefore,
η = (T2 – T2])/r2
= (500 – 300) / 500
= 200/500 .
= 2/5
= 0.4



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