What Will Be The Output Of The Following Code? Void Main () { Int I =

1.	What Will Be The Output Of The Following Code? Void Main () { Int I = 0 , A[3] ; A[i] = I++; Printf (%d,a[i]) ; }
Answer» The output for the above code would be a garbage value. In the statement a[i] = i++; the value of the variable i would GET assigned FIRST to a[i] i.e. a[0] and then the value of I would get incremented by 1. SINCE a[i] i.e. a[1] has not been INITIALIZED, a[i] will have a garbage value. The output for the above code would be a garbage value. In the statement a[i] = i++; the value of the variable i would get assigned first to a[i] i.e. a[0] and then the value of I would get incremented by 1. Since a[i] i.e. a[1] has not been initialized, a[i] will have a garbage value.

What Will Be The Output Of The Following Code? Void Main () { Int I = 0 , A[3] ; A[i] = I++; Printf (%d,a[i]) ; }

Answer»

The output for the above code would be a garbage value. In the statement a[i] = i++; the value of the variable i would GET assigned FIRST to a[i] i.e. a[0] and then the value of I would get incremented by 1. SINCE a[i] i.e. a[1] has not been INITIALIZED, a[i] will have a garbage value.

The output for the above code would be a garbage value. In the statement a[i] = i++; the value of the variable i would get assigned first to a[i] i.e. a[0] and then the value of I would get incremented by 1. Since a[i] i.e. a[1] has not been initialized, a[i] will have a garbage value.

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