1.

Why Does Not The Following Code Give The Desired Result? Int X = 3000, Y = 2000 ; Long Int Z = X * Y ;

Answer»

Here the multiplication is CARRIED out between two ints x and y, and the result that would overflow would be truncated before being assigned to the variable z of type long int. HOWEVER, to GET the correct output, we should use an explicit cast to force long ARITHMETIC as shown below:

long int z = ( long int ) x * y ;

Note that (long int) (x * y) would not give the DESIRED effect.

Here the multiplication is carried out between two ints x and y, and the result that would overflow would be truncated before being assigned to the variable z of type long int. However, to get the correct output, we should use an explicit cast to force long arithmetic as shown below:

long int z = ( long int ) x * y ;

Note that (long int) (x * y) would not give the desired effect.



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