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InterviewSolution
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What will be the `pH` of a solution formed by mixing `40 ml` of `0.10 M HCl` with `10 ml` of `0.45 M NaOH`?A. `12`B. `10`C. `8`D. `6` |
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Answer» Correct Answer - A `M.eq.` of `0.10 M HCl =(0.10)/(1000)xx40=0.004 M` `M.eq.` of `0.45 M NaOH=(0.45xx10)/(1000)=0.0045 M` Now left `[OH^(-)]=0.0045-0.004=5xx10^(-4)M` Total volume `= 50 ml` `[OH^(-)]=(5xx10^(-4))/(50)xx1000` , `[OH^(-)]=1xx10^(-2)` `pOH=2`, `pH=14-pOH=12` |
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