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What will be the pressure-height ratio of air at an altitude of 9144m? (L0=-0.0065 K/m, T0=288.15K, P0=101325 N/m^2)(a) 0.297(b) 0.596(c) 0.359(d) 0.458I had been asked this question in unit test.This intriguing question comes from Standard Atmospheric Model topic in division Atmosphere and Air Data Measurement of Aircraft Performance

Answer»

The CORRECT CHOICE is (a) 0.297

The explanation: The ANSWER is 0.297.

Given L0=-0.0065 K/m, T0=288.15K, P0=101325 N/m^2, H=9144m, we KNOW g0=9.81m/s^2, R=287 J/kg-K

From \(\frac{P}{p_0}\)=[1 + \(\frac{L_0}{T_0}\)H]^\(\frac{-g_0}{RL_0}\)

\(\frac{P}{P_0}\)=[1 + \(\frac{-0.0065}{288.15}\)9144]^\(\frac{-9.81}{287*-0.0065}\)

 \(\frac{P}{P_0}\)=0.297.



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