What will be the resultant velocity?

1.	What will be the resultant velocity?
Answer» Velocity 1 = 30m/s east Velocity 2 = 40m/s north Then, ∅ will be equal to 90° CAUSE north and east direction are PERPENDICULAR to each other. RESULTANT velocity = $\sqrt{30 {}^{2} + 40 {}^{2} + 2 \times 30 \times 40 \times cos90 }$ $\sqrt{900 + 1600 + 2400cos90}$ since cos90° = 0 $\sqrt{900 + 1600}$ $\sqrt{2500}$ $50$ Magnitude of resultant velocity = 50m/s tanß = bsin∅/a+bcos∅ tanß = 40sin90/30+40cos90 tanß = 40/30 {because sin90° = 1 and cos90° = 0} tanß = 4/3 ß= tan-¹(4/3) in North of east Cheers!

Answer»

Velocity 1 = 30m/s east

Velocity 2 = 40m/s north

Then, ∅ will be equal to 90° CAUSE north and east direction are PERPENDICULAR to each other.

RESULTANT velocity =

$\sqrt{30 {}^{2} + 40 {}^{2} + 2 \times 30 \times 40 \times cos90 }$