What will be the work done to stop a moving cycle of mass 30kg which i

1.	What will be the work done to stop a moving cycle of mass 30kg which ismoving with speed 54km/hr ?
Answer» Based on Work - Energy Principle : The Change in the Kinetic Energy of the Cycle is equal to the Net Work done on the Object. W net = mv^2/2-Mu^2/2 Where u is the initial velocity and v is the final velocity Given the mass of the Cycle = 30 kg Intial Velocity (u) = 54km/hr = 54000/3600 = 15m/sec Final Velocity (v) = 0 (because we are stopping the cycle) Substituting all the values in our Net Work done Equation we get : ⇒ Work done to stop the Cycle = 0 - (30 × 15²)/2 = -15³ = -3375 Joules (Negative sign show's that We are doing Work on the Cycle to stop

What will be the work done to stop a moving cycle of mass 30kg which ismoving with speed 54km/hr ?

Answer»

Based on Work - Energy Principle :

The Change in the Kinetic Energy of the Cycle is equal to the Net Work done on the Object.

W net = mv^2/2-Mu^2/2

Where u is the initial velocity and v is the final velocity

Given the mass of the Cycle = 30 kg

Intial Velocity (u) = 54km/hr = 54000/3600 = 15m/sec

Final Velocity (v) = 0 (because we are stopping the cycle)

Substituting all the values in our Net Work done Equation we get :

⇒ Work done to stop the Cycle = 0 - (30 × 15²)/2 = -15³ = -3375 Joules

(Negative sign show's that We are doing Work on the Cycle to stop

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