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When `10 ml` of `0.1 M` acitec acid `(pk_(a)=5.0)` is titrated against `10 ml` of `0.1M` ammonia solution `(pk_(b)=5.0)`,the equivalence point occurs at `pH`A. `5.0`B. `6.0`C. `7.0`D. `9.0` |
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Answer» Correct Answer - C `pK_(a)= -log K_(a)`, `pK_(b)= -log K_(b)` `pH=(1)/(2)[logK_(a)+logK_(w)-logK_(b)]` `=-(1)/(2)[-5+log(1xx10^(-14))-(-5)]` `= -(1)/(2)[-5-14+5]= -(1)/(2)(-14)=7` |
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