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When `._(17)Cl^(35)` undergoes `(n,p)` reaction, the radioisotope formed isa)`._(15)P^(32)`b)`._(16)S^(35)`c)`._(16)S^(34)`d)`._(15)P^(34)`A. `._(15)^(32)P`B. `._(16)^(35)S`C. `._(16)^(34)S`D. `._(15)^(34)P` |
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Answer» Correct Answer - `(b)` `._(17)^(35)C + ._(0)^(1)n - rarr ._(16)^(35)S + ._(1)^(1)H` |
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