When 30 A current flows into the positive terminal of current source 8 V. Calculate the power delivered by the source.(a) -240 W(b) 360 W(c) -430 W(d) 500 WThis question was addressed to me in a national level competition.Query is from Regenerative Braking of DC Series Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives

When 30 A current flows into the positive terminal of current source 8

1.	When 30 A current flows into the positive terminal of current source 8 V. Calculate the power delivered by the source.(a) -240 W(b) 360 W(c) -430 W(d) 500 WThis question was addressed to me in a national level competition.Query is from Regenerative Braking of DC Series Motors topic in chapter Braking of DC Motors & Induction Motors of Electric Drives
Answer» The CORRECT answer is (a) -240 W To EXPLAIN I would say: When the current enters the positive terminal of an ELEMENT it will always absorb the power and when the current leaves the positive terminal it will deliver the power. Power delivered is -30×8=-240 W.

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