1.

When a 9V battery is connected in series with resistors of 0.292,0.392, 0.412, 0.512, and 1292 respectively, how much current wouldflow through the 1292 resistor?

Answer»

There is no current division in a series circuit.Current flow through the component is the same.

Resistances are connected in series.Hence,R=0.2+0.3+0.4+0.5+12=13.4ohms

potential difference,V=9V

I=V/R=9/13.4=0.671 A

Therefore,the amount of current that would flow through 12ohm resistor would be 0.671A



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