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When a ball is thrown up vertically with velocity `v_0`, it reaches a maximum height of h. If one wishes to triple the maximum height then the ball should be thrown with velocityA. `sqrt(3) v_(0)`B. `3v_(0)`C. `9 v_(0)`D. `3//2v_(0)` |
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Answer» Correct Answer - A `(h_(2))/(h_(1))=((u_(2)^(2))/(2g))/((u_(1)^(2))/(2g))rArr (3h_(1))/(h_(1))=(u_(2)^(2))/(v_(0))` `u_(2)^(2)=3v_(0)^(2)rArru_(2)=sqrt(3)v_(0)` |
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