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When a belt moves horizontally at a constantspeed of 1.5 m/s, gravel is falling on it at 5 kg /s . Then the extra power needed to drivethe belt is..pls can anyone answer to the above question plsssssif the answer is correct i will mark the answer as brainlest answer...pls pls pls pls pls pls pls pls pls pls................ |
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Answer» Answer: Velocity of BELT ( v ) = 1.5 m/s Rate at which the MASS of gravel falls = dm/dt = 5 kg/s ∴ FORCE acting on the gravel F = dp/dt = dm/dt (v) = 5 × 1.5 = 7.5 N Power NEEDED P = Fv = 7.5 × 1.5 = 11.25 W Ans... Hope it HELPS you... |
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