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When a disc is rotating with angular velocity `omega` , a particle situated at a distance of 4 cm just begins to slip . If the angular velocity is doubled , at what distance will the particle start to slip ?A. 1 cmB. 2 cmC. 3 cmD. 4 cm |
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Answer» Correct Answer - A Angular velocity = `omega` Centripetal force F = `mr omega^(2)` or `r prop (1)/(omega^(2))` `therefore (r_(1))/(r_(2)) = (omega_(2)^(2))/(omega_(1)^(2))` or `(4)/(r_(2)) = (4omega^(2))/(omega^(2))` or `r_(2) = 1` cm |
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