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When a horizontal force P acts on a cart of mass 20 kg,it moves with a uniform velocity on a horizontal floor.When a force of 1.2 P acts on the cart, it moves with anacceleration of 0.05 m/s. Find the value of P.11. |
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Answer» The horizontal floor has a frictional force F that inhibits the movement of the cart. Acceleration of cart = P - F = 0 as the cart moves with constant velocity and acceleration is 0 So F = P When a force of 1.2 P acts on the cart, acceleration a of the cart is 1.2 P - F = m a 1.2 P - P = 20kg * 0.05 m/sec² P = 1/0.2 = 5 Newtons |
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