When a solution of conductanes `1.342 mho m^(-1)` was placed in a conductivity cell with parallel electrodes the resistance was found to be `170.5` ohm. The area of the electrode is `1.86 xx 10^(-4)` sq meter. Calculate the distance between the two electrodes in meter.

When a solution of conductanes `1.342 mho m^(-1)` was placed in a cond

1.	When a solution of conductanes `1.342 mho m^(-1)` was placed in a conductivity cell with parallel electrodes the resistance was found to be `170.5` ohm. The area of the electrode is `1.86 xx 10^(-4)` sq meter. Calculate the distance between the two electrodes in meter.
Answer» Correct Answer - `4.25xx10^(-2)m`. `K=1.342sec^(-1)" "R=170.5Omega" "A=1.86xx10^(-4)sec.m.` `R=(deltal)/(A)=(l)/(KA)" or "l=RKA=170.5xx1.342xx186xx10^(-4)=4.25xx10^(-2)m`.

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When a solution of conductanes `1.342 mho m^(-1)` was placed in a conductivity cell with parallel electrodes the resistance was found to be `170.5` ohm. The area of the electrode is `1.86 xx 10^(-4)` sq meter. Calculate the distance between the two electrodes in meter.

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