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When a sound wave of wavelength `lamda` is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The ampilitude of wave isA. `lamda`B. `lamda/2`C. `lamda/(2lamda)`D. `lamda/ (4lamda)` |
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Answer» Correct Answer - C `v_(max)= v rArrAomega=v rArr Axx2piv=vlamdaor A=lamda/(2pi)` |
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