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| 1. |
When a substance having mass 3 kg receives 600 cal of heat, its temperatureincreases by 10'C. What is the specificheat of the substance? |
| Answer» 20 J/kg.cExplanation:mass.3 kgchange in temperature.10 cheat.600kcalspecific HEAT= 600÷3×10 = 20 J/kg.c | |