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When a tuning fork vibrates with `1.0 m` or `1.05 m` long wire of a , `5` beats per second are produced in each case. If the frequency of the tuning fork is `5f` (in `Hz`) find `f`. |
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Answer» Correct Answer - 41 Let frequency tuning fork `= f` frequency of wave in wire `= (v)/(2l)` when `l = 1 m` `f_(1) = (v)/(2)` when `l = 1.05m` `f_(2) = (v)/(2 xx (1.05))` `f_(1) - f = 5` , and `f - f_(2) = 5 rArr f_(1) - f_(2) = 10` `rArr (v)/(2)(1 - (1)/(1.05)) = 10` or `v = (20 xx 1.05)/(0.05) = 420 m//s`. `f_(1) = (v)/(2) = 210 Hz`. `f = f_(1) - 5 = 205 Hz`. |
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