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When ammonia reacts with hydrogen chloride gas, it produces white fumes of ammonium chloride. The volume occupied by NH_(3) in glass bulb A is three times more than the volume occupied by HCl in glass bulb B at STP. (i) How many moles of of ammonia are present in glass bulb A? (ii) How many grams of NH_(4)Cl will be formed when the stopper is opened? ("Atomic mass of N = 14, H = 1, Cl = 35.5") (iii) Which gas will remain after completion of the reaction? (iv) Write the chemical reaction involved in this process. |
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Answer» Solution :(i) `"Capacity of "NH_(3)" bulb = 67.2 litre"` `"22.4 litre of "NH_(3)="1 mole"` `therefore"67.2 litre of "NH_(3)=(1)/(22.4)xx67.2="3 moles of "NH_(3)` (ii)`{:("Atomic MASS of 1(N)"=1xx14,=,14g),("Atomic mass of 4(H)"=4xx1,=," 4g"),("Atomic mass of 1(Cl)"=1xx35.5,=,35.5g),(,,""ulbar("53.5g")):}` `"Mass of "NH_(4)Cl=53.5g` (iii) `NH_(3)` (Ammonia) gas will remain after the completion of the reaction. (iv) Chemical equation of the reaction `underset("Ammonia")(NH_(3))+underset("Hydrochloric ACID")(HCl)RARR underset("CHLORIDE")underset("Ammonium")(NH_(4)Cl)` |
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