when break is applied, the speed of cycle is reduced from 2 m/sec to 1

1.	when break is applied, the speed of cycle is reduced from 2 m/sec to 1 m/sec. Determine the work done during this interval ? given mass of cycle along with rider = 10 kg
Answer» Answer: -15 Explanation: Work done is equal to CHANGE in KINETIC ENERGY=(final-initial)Kinetic energy Kinetic energy=(1/2)mv^2 The work done by retardation will come negative

when break is applied, the speed of cycle is reduced from 2 m/sec to 1 m/sec. Determine the work done during this interval ? given mass of cycle along with rider = 10 kg

Answer»

Answer:

-15

Explanation:

Work done is equal to CHANGE in KINETIC ENERGY=(final-initial)Kinetic energy

Kinetic energy=(1/2)mv^2

The work done by retardation will come negative

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when break is applied, the speed of cycle is reduced from 2 m/sec to 1 m/sec. Determine the work done during this interval ? given mass of cycle along with rider = 10 kg​

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when break is applied, the speed of cycle is reduced from 2 m/sec to 1 m/sec. Determine the work done during this interval ? given mass of cycle along with rider = 10 kg