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InterviewSolution
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When initial concentration of a reactant is doubled in a reaction, its half-life period is not affected. The order of the reaction isA. zeroB. firstC. secondD. more than zero but less than first |
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Answer» Correct Answer - B for a zero order reaction `t_(1//2)` is directly proportional to the initial concentration of the reactant ,`[R]_(0)` `t_(1//2)prop[R]_(0)` For a first order reaction , `k=(2.303)/(t)"log"([R]_(0))/([R])` `"at" " t"_(1//2),[R]=[R]_(0)/(2)` So, the above question becomes `k=(2.303)/(t_(1//2))"log"[R]_(0)/([R]_(0)//2)` `t_(1//2=(2.303)/(k)"log"2=(2.303)/(k)xx.3010=(0.693)/(k))` i.e. half-life period is independent of initial concentration of a reactant. |
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