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When the concentration of a reactant in reaction `A rarr B` is increased by `8` times but rate increases only `2` times, the order of the reaction would beA. `2`B. `1//3`C. `4`D. `1//2` |
Answer» Correct Answer - B `r_(1) = k[A]^(n)` `r_(2) = 2r_(1) = k[8A]^(n)` `:. (2r_(1))/(r_(1)) = (8)^(n)` `(2)^(1) = (2)^(3n)` `:. 3n = 1` `n = (1)/(3)`Correct Answer - B `r_(1) = k[A]^(n)` `r_(2) = 2r_(1) = k[8A]^(n)` `:. (2r_(1))/(r_(1)) = (8)^(n)` `(2)^(1) = (2)^(3n)` `:. 3n = 1` `n = (1)/(3)` |
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