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When the concentration of a reactant in reaction `A rarr B` is increased by `8` times but rate increases only `2` times, the order of the reaction would beA. 2B. `(1)/(3)`C. `4`D. `1/2` |
Answer» Correct Answer - B `r_(1) prop [A]^(n) (8[A])^(n)prop 2r_(1)` `((8[A])^(n))/([A]^(n))=2implies 8^(n) = 2 therefore =(1)/(3)` |
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