1.

Where does the poles of the system function of the second filter locate?(a) e^j2π(k+α)M(b) e^j2π(k+α)/M(c) e^j2π(k-α)/M(d) e^jπ(k+α)/MThis question was addressed to me in semester exam.Enquiry is from Structures for FIR Systems in chapter Discrete Time Systems Implementation of Digital Signal Processing

Answer»

Right option is (B) e^j2π(k+α)/M

For explanation I would SAY: The system function of the SECOND filter in the cascade of an FIR realization by frequency sampling method is given by

H2(Z)=\(\sum_{k=0}^{M-1} \frac{H(k+α)}{1-e^{\frac{j2π(k+α)}{M}} z^{-1}}\)

We obtain the poles of the above system function by equating the denominator of the above EQUATION to zero.

=>\(1-e^{\frac{j2π(k+α)}{M}} z^{-1}\)=0

=>z=pk=\(e^{\frac{j2π(k+α)}{M}}\), k=0,1….M-1



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