Which is the correct relationship between `DeltaG^(@)` and equilibrium constant `K_(p)`?A. `K_(p)=-RT log DeltaG^(@)`B. `K_(p)=[E//RT]^(DeltaG^(@))`C. `K_(p)=-DeltaG^(@)//RT`D. `K_(p)=e^(-DeltaG^(@)//RT)`

Which is the correct relationship between `DeltaG^(@)` and equilibrium

1.	Which is the correct relationship between `DeltaG^(@)` and equilibrium constant `K_(p)`?A. `K_(p)=-RT log DeltaG^(@)`B. `K_(p)=[E//RT]^(DeltaG^(@))`C. `K_(p)=-DeltaG^(@)//RT`D. `K_(p)=e^(-DeltaG^(@)//RT)`
Answer» Correct Answer - D

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Which is the correct relationship between `DeltaG^(@)` and equilibrium constant `K_(p)`?A. `K_(p)=-RT log DeltaG^(@)`B. `K_(p)=[E//RT]^(DeltaG^(@))`C. `K_(p)=-DeltaG^(@)//RT`D. `K_(p)=e^(-DeltaG^(@)//RT)`

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