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Which of the following is the correct formula for STE?(a) Es=\(\Big\{H-\frac{V^2}{2g}\Big\}\)(b) Es=\(\Big\{H+\frac{V^2}{g}\Big\}\)(c) Es=\(\Big\{H+\frac{V^2}{2}\Big\}\)(d) Es=\(\Big\{H+\frac{V^2}{2g}\Big\}\)I had been asked this question during an interview.This intriguing question comes from High Performance Climb in division Climb and Descent Performance of Aircraft Performance |
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Answer» Correct option is (d) Es=\(\Big\{H+\frac{V^2}{2G}\Big\}\) |
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