InterviewSolution
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InterviewSolution
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Which of the following is the correct formula of airborne distance with respect to aircraft weight?(a) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2+V_{LOF}^2}{2g}+35\Big\}\)(b) SA=\(\frac{W}{(F_N+D)_{av}}\Big\{\frac{V_{2}^2+V_{LOF}^2}{2g}+35\Big\}\)(c) SA=\(\frac{W}{(F_N+D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\)(d) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\)This question was addressed to me in my homework.The above asked question is from Effect on the Take-off Distances of Flight Variables in portion Take-off and Landing Performance of Aircraft Performance |
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Answer» CORRECT option is (d) SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) To elaborate: The AIRBORNE distance is given by SA=\(\frac{W}{(F_N-D)_{av}}\Big\{\frac{V_{2}^2-V_{LOF}^2}{2g}+35\Big\}\) where W is weight D is drag G is acceleration due to gravity V is velocity FN is NORMAL FORCE. |
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