Which of the following is the correct rate of climb equation?(a) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv(b) τ-\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2(c) τ+\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2(d) τu-\(\frac{1}{2}\)[u^3+u^-1]=EmaxvThis question was posed to me during an online interview.My doubt stems from Climb and Descent Performance with Thrust-Producing Engines topic in division Climb and Descent Performance of Aircraft Performance

Which of the following is the correct rate of climb equation?(a) τu-\

1.	Which of the following is the correct rate of climb equation?(a) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv(b) τ-\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2(c) τ+\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2(d) τu-\(\frac{1}{2}\)[u^3+u^-1]=EmaxvThis question was posed to me during an online interview.My doubt stems from Climb and Descent Performance with Thrust-Producing Engines topic in division Climb and Descent Performance of Aircraft Performance
Answer» The correct choice is (d) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv Best explanation: The correct rate of CLIMB equation is given by τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv where τ is dimensionless thrust, u is airspeed, Emax is ENDURANCE and γ is the ANGLE at which the force is acting on the AIRCRAFT.

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