1.

Which of the following nuclides are `beta^(ɵ)` and `beta^(o+)` emitter, and stable nuclides? `._(20)Ca^(49)` b. `._(80)Hg^(195)` c. `._(82)Pb^(208)` d. `._(5)B^(8)` e. `._(67)Ho^(150)` f. `._(13)Al^(30)` e. `._(50)Sn^(120)` g. `._(36)Kr^(94)`

Answer» `beta^(ɵ)`- emitter `implies` a. `._(20)Ca^(49)` f. `._(13)Al^(30)` h. `._(36)Kr^(94)`
All of them have `Z` less than 82.
a. `._(20)Ca^(49) implies (n)/(p) = (29)/(20) = 1.45` `[{:(n//p "higher and is"),("lowered by"),(beta^(ɵ)-"emission"),((atomic weight" lt 82)):}]`
f. `._(13)Al^(30) implies (n)/(p) = (17)/(13) = 1.3`
h. `._(36)Kr^(94) implies (n)/(p) = (58)/(36) = 1.3`
`beta^(o+)`-emitter `implies` b. `._(80)Hg^(195)` d. `._(5)B^(8)` e. `._(67)Ho^(150)`
All of them are `Z` less than 82.
b. `._(80)Hg^(195) , (n)/(p) = (115)/(80) = 1.43` `[{:(n//p "is lower than the"),("stability belt for Hg"),(n//p "should be equal"),("to" 153):}]`
`n//p` is lower than 1.53, so it will emit `beta^(o+)` to incrase `n//p` ratio.
d. `._(5)B^(8)`,(n)/(p) = (3)/(5) = 0.6`, (for stability `n//p` ratio - 1)
`n//p` is lower than 1. `(Z "up" 20, (n)/(p) = 1)` It is `beta^(o+)` emitter
e. `._(67)Ho^(150), (n)/(p) = (33)/(67) = 1.2` `({:("For stability with" Z gt 60),(n//p "should be" 1.50):})`
`n//p` is lower than 1.5. So `beta^(o+)` emitter.
Stable nuclides
`._(92)Pb^(208)`, `._(50)Sn^(120)`
Both have even number `p` and even number of `n`. These are stable nuclides.


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