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Which of the following option gives correct vector form for equation v2 = u2 + 2as?1. \(\overrightarrow{v} \times \overrightarrow{v}=\overrightarrow{u}\times \overrightarrow{u}+2\overrightarrow{a} \times \overrightarrow{s}\)2. \(\overrightarrow{v} \times \overrightarrow{v}=\overrightarrow{u}\times \overrightarrow{u}+2\overrightarrow{a} . \overrightarrow{s}\)3. \(\overrightarrow{v}.\overrightarrow{v}=\overrightarrow{u}.\overrightarrow{u}+2\overrightarrow{a} \times \overrightarrow{s}\)4. \(\overrightarrow{v}.\overrightarrow{v}=\overrightarrow{u}.\overrightarrow{u}+2\overrightarrow{a}.\overrightarrow{s}\) |
Answer» Correct Answer - Option 4 : \(\overrightarrow{v}.\overrightarrow{v}=\overrightarrow{u}.\overrightarrow{u}+2\overrightarrow{a}.\overrightarrow{s}\) CONCEPT:.
\(\overrightarrow{v}=\overrightarrow{u}+\overrightarrow{a}t\) \(\overrightarrow{s}=\overrightarrow{u}t+{1 \over 2} \overrightarrow{a}t^2\) \(\overrightarrow{v}.\overrightarrow{v}=\overrightarrow{u}.\overrightarrow{u}+2\overrightarrow{a}.\overrightarrow{s}\) EXPLANATION: The third equation of motionv2= u2+ 2as in the vector form is written as: \(\overrightarrow{v}.\overrightarrow{v}=\overrightarrow{u}.\overrightarrow{u}+2\overrightarrow{a}.\overrightarrow{s}\) \(vv ~cos0 =uu ~cos0 + 2as ~cos0 \) \(v^2 =u^2+ 2as \) So the correct answer isoption 4. |
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