Which of the following query returns the average throughput for the most recent sessions?(a) SELECT command_count*duration AS [Throughput] FROM sys.dm_cdc_log_scan_sessions WHERE session_id = 0(b) SELECT command_count/duration AS [Throughput] FROM sys.dm_cdc_log_scan_sessions WHERE session_id = 0(c) SELECT command_count/duration AS [Throughput] FROM sys.dm_cdc_log_scan_sesss WHERE session_id = 0(d) None of the mentionedI had been asked this question during an interview.This intriguing question comes from SQL Audit in portion Monitoring and Auditing of SQL Server

Which of the following query returns the average throughput for the mo

1.	Which of the following query returns the average throughput for the most recent sessions?(a) SELECT command_count*duration AS [Throughput] FROM sys.dm_cdc_log_scan_sessions WHERE session_id = 0(b) SELECT command_count/duration AS [Throughput] FROM sys.dm_cdc_log_scan_sessions WHERE session_id = 0(c) SELECT command_count/duration AS [Throughput] FROM sys.dm_cdc_log_scan_sesss WHERE session_id = 0(d) None of the mentionedI had been asked this question during an interview.This intriguing question comes from SQL Audit in portion Monitoring and Auditing of SQL Server
Answer» The correct option is (B) SELECT command_count/duration AS [Throughput] FROM sys.dm_cdc_log_scan_sessions WHERE session_id = 0 Best EXPLANATION: To determine the throughput of a session, divide the value in the command_count COLUMN by the value in the duration column.

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