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Which of the following values of x do not satisfy the inequality x2 – 3x + 2 > 0 at all.(a) 1 < \(x\) < 2 (b) – 1 > \(x\) > – 2 (c) 0 < \(x\)< 2 (d) 0 > \(x\) > – 2 |
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Answer» (a) 1 < x < 2 x2 – 3\(x\) + 2 > 0 ⇒ (\(x\) – 2) (\(x\) – 1) > 0 ⇒ (\(x\) – 2) > 0, (\(x\) – 1) < 0 or (\(x\) – 2) < 0, (\(x\) – 1) > 0 ⇒ \(x\) > 2, \(x\) < 1 or \(x\) < 2, \(x\) > 1 ⇒ \(x\) < 1 or \(x\) > 2 ∴ No value of x which lies between these extremes, i.e., 1 and 2 satisfies the inequality, i.e., 1 < \(x\) < 2 is the solution set not satisfying the inequality x2 – 3\(x\) + 2 > 0 at all. |
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