(i)\(\frac{-4}{3}\) and\( \frac{-8}{7}\) have different denominators. Therefore, we take LCM of 3 and 7 that is 21. 

Now,

\(\frac{-4}{3}=\frac{-4\times7}{3\times7}=\frac{-28}{21}\)

And,

\(\frac{-8}{7}=\frac{-8\times3}{7\times3}=\frac{-24}{21}\)

Since, -24 > -28

Therefore,\(\frac{-24}{21}\)>\(\frac{-28}{21}\)

Hence,\(\frac{-8}{7}\)>\(\frac{-4}{3}\)

(ii)

\(\frac{-7}{9}=\frac{-7\times-1}{-9\times-1}=\frac{-7}{9}\)

\(\frac{-7}{9}\)and\(\frac{-5}{8}\) have different denominators. Therefore, we take LCM of 9 and 8 that is 72.

 Now,

\(\frac{-7}{9}=\frac{-7\times8}{9\times8}=\frac{-56}{72}\)

And,

\(\frac{-5}{8}=\frac{-5\times9}{8\times9}=\frac{-45}{72}\)

Since, -45 > -56

Therefore, \(\frac{-45}{72}\)>\(\frac{-56}{72}\)

Hence, \(\frac{-5}{8}\)>\(\frac{-7}{9}\)

(iii)

\(\frac{-4}{5}=\frac{-4\times-1}{-5\times-1}=\frac{-4}{5}\)

\(\frac{-1}{3}\) and\(\frac{-4}{5}\) have different denominators. Therefore, we take LCM of 3 and 5 that is 15. 

Now,

\(\frac{-1}{3}=\frac{-1\times5}{3\times5}=\frac{-5}{15}\)

And,

\(\frac{-4}{5}=\frac{-4\times3}{5\times3}=\frac{-12}{15}\)

Since, -5 > -12

Therefore,  \(\frac{-5}{15}\)>\(\frac{-12}{15}\)

Hence, \(\frac{-1}{3}\)>\(\frac{-4}{5}\)

(iv)

\(\frac{-9}{-13}=\frac{9\times-1}{-13\times-1}=\frac{-9}{13}\)

And,

\(\frac{7}{-12}=\frac{7\times-1}{-12\times-1}=\frac{-7}{12}\)

\(\frac{-9}{13}\)and \(\frac{-7}{12}\)have different denominators.

Therefore, we take LCM of 13 and 12 that is 156. Now,

\(\frac{-9}{13}=\frac{-9\times-12}{13\times12}=\frac{-108}{156}\)

And,

\(\frac{-7}{12}=\frac{-7\times-13}{12\times13}=\frac{-91}{156}\)

Since, -91 > -108

Therefore, \(\frac{-91}{156}\)>\(\frac{-108}{156}\)

Hence,  \(\frac{-7}{12}\)>\(\frac{-9}{13}\)

(v)

\(\frac{-4}{5}=\frac{4\times-1}{-5\times-1}=\frac{-4}{5}\)

\(\frac{-7}{10}\)and\(\frac{-4}{5}\) have different denominators.

Therefore, we take LCM of 10 and 5 that is 10. Now,

\(\frac{-7}{10}=\frac{-7\times1}{10\times1}=\frac{-7}{10}\)

And,

\(\frac{-4}{5}=\frac{-4\times2}{5\times2}=\frac{-8}{10}\)

Since, -7 > -8

Therefore, \(\frac{-7}{10}\)>\(\frac{-8}{10}\)

Hence, \(\frac{-7}{10}\)>\(\frac{-4}{5}\)

(vi)

 We can write-3=\(\frac{-3}{1}\)

\(\frac{-3}{1}\) and \(\frac{-12}{5}\) have different denominators. Therefore, we take LCM of 1 and 5 that is 5. 

Now,

\(\frac{-12}{5}=\frac{-12\times1}{5\times1}=\frac{-12}{5}\)

And,

\(\frac{-3}{1}=\frac{-3\times5}{1\times5}=\frac{-15}{5}\)

Since, -12 > -15

Therefore, \(\frac{-12}{5}\)>\(\frac{-15}{5}\)

Hence,  \(\frac{-12}{5}\)>-3