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Which one of the following is correct? The function `F:ArarrR` where `A={x in R,-(pi)/(2)ltxlt(pi)/(2)}` defined by f(x) = tan x.A. InjectiveB. Not injectiveC. BijectiveD. Not bijective

Answer» Correct Answer - A
`because` f(x)=tanx
f(x) is increasing in the interval `(-(pi)/(2),(pi)/(2))`
Hence, f(x) is injective in the interval `(-(pi)/(2),(pi)/(2))`


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